Displaying Parameters in Response in tableView

Introduction

In this article, we will discuss how to display parameters in response in a tableView. We will cover the steps required to achieve this and provide examples of code to help illustrate the process.

Background

A tableView is a control used in iOS applications to display a collection of data in a table format. It is commonly used to display lists of items, such as contact information or products. When using a tableView, it is often necessary to retrieve data from a server and display it in the table view. In this article, we will focus on how to do this.

Step 1: Retrieving Data from Server

To display data in a tableView, you first need to retrieve the data from your server. This can be done using a networking library such as AFNetworking. The following code snippet shows an example of how to use AFNetworking to retrieve data from a server:

NSArray *ResponseArray = [NSJSONSerialization JSONObjectWithData:responseObject options: kNilOptions error: nil];

However, this code is not sufficient on its own. We need to parse the JSON response and extract the relevant information.

Step 2: Parsing JSON Response

To parse the JSON response, we can use the mutableCopy method to create a mutable array of dictionaries, where each dictionary represents an item in our table view. The following code snippet shows an example of how to do this:

NSMutableArray *finalArray = [NSMutableArray array];
for (NSDictionary *temp in ResponseArray) {
    [finalArray addObject:temp[@"name"]];
}

However, this code is still incomplete. We need to use the mutableCopy method to create a mutable copy of our ResponseArray, and then loop through each item in the array to extract the relevant information.

Step 3: Creating Cell Content

To display data in our table view, we need to create cell content for each item in our table view. This can be done by creating a new instance of UITableViewCell and setting its text label’s text property to the relevant information from our parsed JSON response.

The following code snippet shows an example of how to do this:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
    static NSString *simpleTableIdentifier = @"cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];

    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:simpleTableIdentifier];
    }

    NSDictionary *content = [menuItems objectAtIndex:indexPath.row];  
    cell.textLabel.text = [NSString stringWithFormat:@"Name:%@, Mobile:%@,  Email:%@,  Relation:%@",content[@"name"],content[@"mobile_no"],content[@"email_id"],content[@"relation"]];

    return cell;
}

However, this code is still incomplete. We need to use the StringWithFormat: method to create a string with the relevant information from our parsed JSON response.

Step 4: Updating Code

To update the code to use StringWithFormat: instead of NSString StringWithFormat:, we can modify the following lines of code:

cell.name.text = [NSString StringWithFormat:@"Name:%@",content[@"name"]];
cell.email.text = [NSString StringWithFormat:@"email:%@",content[@"email"]];
cell.mobile.text = [NSString StringWithFormat:@"mobile:%@",content[@"mobile"]];
cell.relation.text = [NSString StringWithFormat:@"relation:%@",content[@"relation"]];

We can replace these lines with the following code:

cell.name.text = [NSString StringWithFormat:@"Name:%@", content[@"name"]];
cell.email.text = [NSString StringWithFormat:@"email:%@", content[@"email"]];
cell.mobile.text = [NSString StringWithFormat:@"mobile:%@", content[@"mobile"]];
cell.relation.text = [NSString StringWithFormat:@"relation:%@", content[@"relation"]];

However, this code still uses StringWithFormat: which is not necessary. We can simplify the code to use the following lines:

cell.name.text = [NSString stringWithFormat:@"Name:%@", content[@"name"]];
cell.email.text = [NSString stringWithFormat:@"email:%@", content[@"email"]];
cell.mobile.text = [NSString stringWithFormat:@"mobile:%@", content[@"mobile"]];
cell.relation.text = [NSString stringWithFormat:@"relation:%@", content[@"relation"]];

Step 5: Updating Cell Identifier

To update the code to use a custom cell identifier, we can modify the following line of code:

static NSString *simpleTableIdentifier = @"cell";

We can replace this line with the following code:

static NSString *CellIdentifier = @"EmergencyContactCell";

Updated Code

Here is the updated code that displays parameters in response in a tableView:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
    static NSString *CellIdentifier = @"EmergencyContactCell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];

    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
    }

    NSDictionary *content = [menuItems objectAtIndex:indexPath.row];

    cell.name.text = [NSString stringWithFormat:@"Name:%@", content[@"name"]];
    cell.email.text = [NSString stringWithFormat:@"email:%@", content[@"email"]];
    cell.mobile.text = [NSString stringWithFormat:@"mobile:%@", content[@"mobile"]];
    cell.relation.text = [NSString stringWithFormat:@"relation:%@", content[@"relation"]];

    return cell;
}

Conclusion

In this article, we discussed how to display parameters in response in a tableView. We covered the steps required to achieve this and provided examples of code to help illustrate the process. By following these steps and using the updated code, you should be able to display data from your server in a tableView.

Last modified on 2024-07-15